35x^2+2x=1

Solution for 35x^2+2x=1 equation:

35x^2+2x=1

We move all terms to the left:

35x^2+2x-(1)=0

a = 35; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·35·(-1)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-12}{2*35}=\frac{-14}{70}
=-1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+12}{2*35}=\frac{10}{70}
=1/7
$